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If alpha+beta=pi/2a n dbeta+gamma=alpha,...

If `alpha+beta=pi/2a n dbeta+gamma=alpha,` then `tanalpha` equals `2(tanbeta+tangamma)` (b) `tanbeta+tangamma` `tanbeta+2tangamma` (d) `2tanbeta+tangamma`

A

`2(tan beta + tan gamma)`

B

`tan beta + tan gamma `

C

`tan beta+ 2 tan gamma`

D

`2 tan beta + tan gamma`

Text Solution

Verified by Experts

The correct Answer is:
C
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TARGET PUBLICATION-TRIGONOMETRIC FUNCTIONS OF COMPOUND ANGLES -CRITICAL THINKING
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