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The value of cos(270^@+theta)cos(90^@+th...

The value of `cos(270^@+theta)cos(90^@+theta)-sin(270^@-theta)costheta` is

A

0

B

`-1`

C

`1/2`

D

1

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The correct Answer is:
D
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If cot theta=-(7)/(24),(270^(@)

Prove that : (i) sinthetacos(90^(@)-theta)+sin(90^(@)-theta)costheta=1 (ii) sectheta" cosec"(90^(@)-theta)-tanthetacot(90^(@)-theta)=1 (iii) (sintheta*sec(90^(@)-theta)cot(90^(@)-theta))/("cosec"(90^(@)-theta)*costheta*tantheta)-(tan(90^(@)-theta))/(cottheta)=0 (iv) (1+sin(90^(@)-theta))/(cos(90^(@)-0))+(cos(90^(@)-theta))/(1+sin(90^(@)-0))=2"cosec"theta

sin theta cos(90^@ -theta) +cos theta sin(90^@ -theta) = ?

Prove that :(sin theta cos(90^(0)-theta)cos theta)/(sin(90^(0)-theta))+(cos theta sin(90^(0)-theta)sin theta)/(cos(90^(@)-theta))=1csc^(2)(90^(@)-theta)-tan^(2)theta=cos^(2)(90^(@)-theta)+cos^(2)theta

TARGET PUBLICATION-TRIGONOMETRIC FUNCTIONS OF COMPOUND ANGLES -COMPETITIVE THINKING
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