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2 sin A cos ^(3) A-2 sin ^(3) A cos A=...

`2 sin A cos ^(3) A-2 sin ^(3) A cos A=`

A

`sin 4A`

B

`1/2 sin 4 A`

C

`1/4 sin 4A`

D

`1/8 sin 4A`

Text Solution

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The correct Answer is:
B
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TARGET PUBLICATION-TRIGONOMETRIC FUNCTIONS OF COMPOUND ANGLES -COMPETITIVE THINKING
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