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cos 2 alpha =(3 cos 2 beta -1)/( 3-cos 2...

`cos 2 alpha =(3 cos 2 beta -1)/( 3-cos 2 beta),` then `tan alpha=`

A

`sqrt2 tan beta`

B

`(tan beta)/( sqrt2)`

C

`(tan ^(2) beta)/( sqrt2)`

D

`tan beta`

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The correct Answer is:
A
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