Home
Class 11
MATHS
The equation of a line perpendicular to ...

The equation of a line perpendicular to line `ax+by+c=0` and passing through `(a,b)` is equal to

A

`bx-ay=0`

B

` bx+ay-2ab=0`

C

`bx+ay=0`

D

`bx-ay+ 2ab=0`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • STRAIGHT LINE

    TARGET PUBLICATION|Exercise CRITICAL THINKING|68 Videos
  • STRAIGHT LINE

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING|99 Videos
  • SETS, RELATIONS AND FUNCTIONS

    TARGET PUBLICATION|Exercise EVALUATION TEST|14 Videos
  • TRIGONOMETRIC FUNCTIONS OF COMPOUND ANGLES

    TARGET PUBLICATION|Exercise EVALUATION TEST|12 Videos

Similar Questions

Explore conceptually related problems

Find the equation of a line perpendicular to the line x-2y+3=0 and passing through the point (1,-2)

Find the equation of a line perpendicular to the line x-2y+3=0 and passing through the point (1, -2) .

Find the equation of the line perpendicular to the line (x)/(a)-(y)/(b)=1 and passing through a point at which it cuts the x-axis.

Find the equation of the line perpendicular to x-axis and passing through the origin.

The equation of the line perpendicular to Y-axis and passing through point (-5,7) is "_______" .

Prove that the equation of the st.line perpendicular to Ax+By+C=0 and passing through (x_(1),y_(1)) is Bx-Ay=Bx_(1)-Ay_(1) .

The equation of line equally inclined to coordinate axes and passing through (-3,2,-5) is

Find the equation of a line perpendicular to the line (x)/(a)+(y)/(b)-1 and passes through the mid-point of the line segment lying between the axes of the given line.

The equation of line equally inclined to co -ordinate axes and passing through (3,2,-5) is