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If vertices of a parallelogram are respe...

If vertices of a parallelogram are respectively `(0,0), (1,0) ,(2,2) and (1,2)` then angle between diagonals is

A

`(pi)/(3)`

B

`(pi)/(2)`

C

`(3pi)/(2)`

D

`(pi)/(4)`

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The correct Answer is:
To find the angle between the diagonals of the parallelogram with vertices at \( A(0,0) \), \( B(1,0) \), \( C(2,2) \), and \( D(1,2) \), we can follow these steps: ### Step 1: Identify the diagonals The diagonals of the parallelogram are \( AC \) and \( BD \). ### Step 2: Find the coordinates of the diagonals - Diagonal \( AC \) connects points \( A(0,0) \) and \( C(2,2) \). - Diagonal \( BD \) connects points \( B(1,0) \) and \( D(1,2) \). ### Step 3: Calculate the slopes of the diagonals The slope \( m \) of a line connecting two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by the formula: \[ m = \frac{y_2 - y_1}{x_2 - x_1} \] #### For diagonal \( AC \): - \( A(0,0) \) and \( C(2,2) \): \[ m_{AC} = \frac{2 - 0}{2 - 0} = \frac{2}{2} = 1 \] #### For diagonal \( BD \): - \( B(1,0) \) and \( D(1,2) \): \[ m_{BD} = \frac{2 - 0}{1 - 1} = \frac{2}{0} \] Since the denominator is zero, the slope \( m_{BD} \) is undefined, indicating that line \( BD \) is vertical. ### Step 4: Use the formula for the angle between two lines The angle \( \theta \) between two lines with slopes \( m_1 \) and \( m_2 \) is given by: \[ \tan \theta = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right| \] Here, \( m_1 = 1 \) (slope of \( AC \)) and \( m_2 \) is undefined (slope of \( BD \)). ### Step 5: Analyze the angle Since one of the slopes is undefined, it means that one of the lines is vertical. The angle between a vertical line and any line with a defined slope can be calculated as follows: - The angle between a vertical line and a line with slope \( m \) is given by: \[ \tan \theta = \left| \frac{1 - m}{1 + m \cdot \infty} \right| = \infty \] This implies that \( \theta = \frac{\pi}{2} \) radians or \( 90^\circ \). ### Final Answer The angle between the diagonals \( AC \) and \( BD \) is \( 90^\circ \). ---
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