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If A and B are two events such that P(A...

If A and B are two events such that `P(A uu B) = (5)/(6) , P(A nn B) = (1)/(3) ` and `P(barB) = (1)/(3)` then P(A) =

A

`(1)/(4)`

B

`(1)/(3)`

C

`(1)/(4)`

D

`(2)/(3)`

Text Solution

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To solve the problem, we need to find \( P(A) \) given the following information: 1. \( P(A \cup B) = \frac{5}{6} \) 2. \( P(A \cap B) = \frac{1}{3} \) 3. \( P(\bar{B}) = \frac{1}{3} \) ### Step-by-Step Solution: **Step 1: Find \( P(B) \)** We know that the probability of an event plus the probability of its complement equals 1. Thus, we can find \( P(B) \) as follows: \[ P(B) = 1 - P(\bar{B}) = 1 - \frac{1}{3} = \frac{2}{3} \] **Step 2: Use the formula for the union of two events** The formula for the probability of the union of two events \( A \) and \( B \) is given by: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \] We can rearrange this formula to solve for \( P(A) \): \[ P(A) = P(A \cup B) - P(B) + P(A \cap B) \] **Step 3: Substitute the known values into the formula** Now we can substitute the values we have into the rearranged formula: \[ P(A) = P(A \cup B) - P(B) + P(A \cap B) \] Substituting the known values: \[ P(A) = \frac{5}{6} - \frac{2}{3} + \frac{1}{3} \] **Step 4: Simplify the expression** To simplify the expression, we first convert all fractions to have a common denominator. The common denominator for 6 and 3 is 6: \[ P(A) = \frac{5}{6} - \frac{4}{6} + \frac{2}{6} \] Now, combine the fractions: \[ P(A) = \frac{5 - 4 + 2}{6} = \frac{3}{6} = \frac{1}{2} \] ### Final Answer: Thus, the probability \( P(A) \) is: \[ P(A) = \frac{1}{2} \]
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TARGET PUBLICATION-PROBABILITY-CLASSICAL THINKING(ADDITION THEOREM AND CONDITIONAL PROBABILITY )
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  11. If A and B are any two events associated with an experiment, then

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  12. Events A and B are independent if

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  13. If the events A and B are mutually exclusive, then P( A/B) =

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  14. A and B are two events such that P(A)= 0.8, P(B) = 0.6 and P (Ann B) =...

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