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If P(E(1)) = p(1) and P(E(2)) = p(2) a...

If `P(E_(1)) = p_(1) and P(E_(2)) = p_(2)` and `E_(1)` and `E_(2)` are independent then P( neither `E_(1)` nor `E_(2)`)=

A

`(1-p_(1))(1-p_(2))`

B

`1-(p_(1) +p_(2))`

C

`p_(1)+p_(2)+p_(1)p_(2)`

D

`p_(1)-p_(2)`

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The correct Answer is:
A
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TARGET PUBLICATION-PROBABILITY-CRITICAL THINKING (ADDITION THEOREM AND CONDITIONAL PROBABILITY)
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