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If P(A) = P(B) = x and P(A nn B) = 0.14...

If `P(A) = P(B) = x ` and `P(A nn B) = 0.14,` then `P(A' nn B') =(1)/(3)`, then find the value of x

A

`(1)/(2)`

B

`(1)/(3)`

C

`(1)/(4)`

D

`(1)/(6)`

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The correct Answer is:
A
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TARGET PUBLICATION-PROBABILITY-COMPETITIVE THINKING (ADDITION THEOREM AND CONDITIONAL PROBABILITY)
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