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Matrix A=[[1, 0, -k], [2, 1, 3], [k, 0, ...

Matrix `A=[[1, 0, -k], [2, 1, 3], [k, 0, 1]]` is invertible for

A

`k=1`

B

`k=-1`

C

`k=0`

D

All real k

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The correct Answer is:
D
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TARGET PUBLICATION-MATRICES-COMPETITIVE THINKING (Inverse off a matrix )
  1. A=[(2,-2),(-2,2)], B=[(1,1),(1,1)] then

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  2. If A=[(1,lambda,2),(1,2,5),(2,1,1)] is not invertible then lambda=?

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  3. Matrix A=[[1, 0, -k], [2, 1, 3], [k, 0, 1]] is invertible for

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  4. The matrix [(lamda,-1,4),(-3,0,1),(-1,1,2)] is invertible if

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  6. IF A=[(1,1,0),(2,1,5),(1,2,1)],then a(11) A(21) +a(12)+a(12)A(22)+a...

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  7. Matrix A=[(1,2,3),(1,1,5),(2,4,7)], then the value of a(31)A(31)+a(32)...

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  8. If X=[[-x, -y], [z, t]], then transpose of adjX is

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  9. Let A=[(1,0,0),(5,2,0),(-1,6,1)], then the adjoint of A is

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  10. if A=[[2,-3],[-4,1]] then (3A^2+12A)=?

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  11. If A=[(1,-1,1),(0,2,-3),(2,1,0)],B=(adjA) and C=5A, then (|adjB|)/(|C|...

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  12. If A=[{:(3,2),(1,4):}], then what is A (adj A) equal to ?

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  13. If A=[(cos x, sin x),(-sin x,cos x)], then A(adj A)=

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