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A=[{:(0,3),(2,0):}] and A^(-1)=lambda (a...

A=`[{:(0,3),(2,0):}] and A^(-1)=lambda` (adj, A) then `lambda` is equal to

A

`(-1)/(6)`

B

`(1)/(3)`

C

`(-1)/(3)`

D

`(1)/(6)`

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TARGET PUBLICATION-MATRICES-COMPETITIVE THINKING (Inverse off a matrix )
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