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If bara,barb and barc are three non-copl...

If `bara,barb` and `barc` are three non-coplanar vectors, then : `(bara + barb + barc) · [(bara + barb) xx (bara + barc)]` =

A

0

B

`[bara" "barb" "barc]`

C

`-[bar(a)bar(b)bar(c)]`

D

`2[bara,barb,barc]`

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The correct Answer is:
C
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