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TARGET PUBLICATION-DEFINITE INTEGRALS-CRITICAL THINKING
- int(0)^(pi//2) e^(x^(2))/(e^(x^(2)+ e^((pi/2-x)^(2))))dx=
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- int(0)^(pi//2)(sin^(3//2)x)/(sin^(3//2)x+cos^(3//2)x)dx
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- The value of int(0)^(pi//2)(dx)/(1+tan^(3)x) is
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- The value of int(0)^(pi)e^(cos^(2)x)cos^(5)3x dx is
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- The value of int(0)^(pi//2)lot((4+3sinx)/(4+3cosx))dx is
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- underset(0)overset(pi//2)int (d theta)/(1+tantheta)=
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- Evaluate the following : int(0)^(pi)x sin^(3)x dx
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- int(0)^((pi)/(2))log(sinx)dx=int(0)^((pi)/(2))log(cosx)dx=(pi)/(2)log....
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- int0^pixlogsinx dx
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- The value of int(0)^(pi//4) log (1+ tan theta ) d theta is equal to
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- The value of int0 1tan^(-1)((2x-1)/(1+x-x^2))dx is (A) 1 (B) 0 (C) -1 ...
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- int(0)^(pi)(x tanx)/(sec x +tan x)dx
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- Evaluate the following : int(pi//6)^(pi//3)(1)/(1+sqrt(cotx))dx
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- If f(a+b - x) = f(x) , then int(a)^(b) x f(x) dx is equal to
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- If f(x)=f(2-x) then int(0. 5)^1.5 xf(x)dx=
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- If : int(0)^(2a)f(x)dx=2.int(0)^(a)f(x)dx, then :
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- int(0)^(pi)sin^(2)x dx is equal to
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- int(0)^(pi)|cosx|dx=?
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- The value of int(0)^(2pi)cos^(99)x dx is
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- int(0)^(pi)log sin^(2)x dx=
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