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I10=int0^(pi/2)x^(10)sinx dx then I10+90...

`I_10=int_0^(pi/2)x^(10)sinx dx` then `I_10+90I_8` is (A) `10(pi/2)^6` (B) `10(pi/2)^9` (C) `10(pi/2)^8` (D) `10(pi/2)^7`

A

`10((pi)/2)^(6)`

B

`10((pi)/2)^(9)`

C

`10((pi)/2)^(7)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
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