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The area of the region bounded by the cu...

The area of the region bounded by the curves `y=sqrt[[1+sinx]/cosx]` and `y=sqrt[[1-sinx]/cosx]` bounded by the lines x=0 and `x=pi/4` is

A

`int_(0)^(sqrt(2)-1)(t)/((1+t^(2))sqrt(1-t^(2)))dt`

B

`int_(0)^(sqrt(2)-1)(4t)/((1+t^(2))sqrt(1-t^(2)))dt`

C

`int_(0)^(sqrt(2)+1)(4t)/((1+t^(2))sqrt(1-t^(2)))dt`

D

`int_(0)^(sqrt(2)+1)(t)/((1+t^(2))sqrt(1-t^(2)))dt`

Text Solution

Verified by Experts

The correct Answer is:
B
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TARGET PUBLICATION-APPICATIONS OF DEFINITE INTEGRAL-EVALUATION TEST
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  8. The area bounded by the curves y = cos x and y = sin x between the ord...

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  12. Find the area of the region bounded by the curves y^(2)=x+1 and y^(2)=...

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  13. The area of the closed figure bounded by x=-1, y=0, y=x^(2)+x+1, and t...

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  14. The area of the region bounded by the curves x^(2)+4y^(2)=4 " and " 4y...

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  15. The slope of the tangent to a curve y=f(x) at (x,f(x)) is 2x+1. If the...

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  16. The area bounded by y = sin^(-1)x,x=(1)/(sqrt(2)) and X-axis is

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  17. The area of the region bounded by the parabola (y-2)^(2) = x- 1, the t...

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  18. The area of the region bounded by the curves y=sqrt[[1+sinx]/cosx] and...

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