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For a random variable X, if Var (X) = 4 ...

For a random variable X, if Var (X) = 4 and `E(X^(2))=13`, the value of E(X) is

A

3

B

4

C

5

D

6

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( E(X) \) given that \( \text{Var}(X) = 4 \) and \( E(X^2) = 13 \), we can use the relationship between variance, expected value, and the expected value of the square of a random variable. ### Step-by-Step Solution: 1. **Recall the formula for variance**: The variance of a random variable \( X \) is given by the formula: \[ \text{Var}(X) = E(X^2) - (E(X))^2 \] 2. **Substitute the known values into the formula**: We know that \( \text{Var}(X) = 4 \) and \( E(X^2) = 13 \). Plugging these values into the variance formula gives: \[ 4 = 13 - (E(X))^2 \] 3. **Rearrange the equation to solve for \( (E(X))^2 \)**: Rearranging the equation, we get: \[ (E(X))^2 = 13 - 4 \] \[ (E(X))^2 = 9 \] 4. **Take the square root to find \( E(X) \)**: To find \( E(X) \), take the square root of both sides: \[ E(X) = \sqrt{9} \] \[ E(X) = 3 \] Thus, the value of \( E(X) \) is \( 3 \).
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