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The distance travelled by a ray of light...

The distance travelled by a ray of light in two media, in the same time are in the ratio 2 : 3. The ratio of refractive index of the first medium to second medium is

A

`3 : 2`

B

`4 : 9`

C

`2 : 3`

D

`9 : 8`

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The correct Answer is:
To solve the problem, we need to find the ratio of the refractive indices of two media based on the distances traveled by light in those media in the same time. ### Step-by-Step Solution: 1. **Understanding the Given Ratio**: We are given that the distances traveled by a ray of light in two media are in the ratio of 2:3. Let's denote: - Distance in medium 1 (d1) = 2x - Distance in medium 2 (d2) = 3x where x is a common factor. 2. **Using the Relation of Speed**: The speed of light in a medium is given by the formula: \[ v = \frac{d}{t} \] Since the time (t) taken in both media is the same, we can write: \[ \frac{v_1}{v_2} = \frac{d_1}{d_2} \] Substituting the distances: \[ \frac{v_1}{v_2} = \frac{2x}{3x} = \frac{2}{3} \] 3. **Relating Refractive Index to Speed**: The refractive index (μ) of a medium is defined as: \[ \mu = \frac{c}{v} \] where c is the speed of light in vacuum (or air) and v is the speed of light in the medium. For two media, we can write: \[ \frac{\mu_1}{\mu_2} = \frac{v_2}{v_1} \] 4. **Substituting the Speed Ratio**: From our earlier step, we found that: \[ \frac{v_1}{v_2} = \frac{2}{3} \] Therefore, the inverse gives: \[ \frac{v_2}{v_1} = \frac{3}{2} \] 5. **Finding the Ratio of Refractive Indices**: Now substituting this into the refractive index ratio: \[ \frac{\mu_1}{\mu_2} = \frac{v_2}{v_1} = \frac{3}{2} \] ### Final Answer: The ratio of the refractive index of the first medium to the second medium is: \[ \frac{\mu_1}{\mu_2} = \frac{3}{2} \]
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