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A candle flame 2 cm high is placed at di...

A candle flame 2 cm high is placed at distance of 2 meter from a wall. How far from the wall must a concave mirror to placed in order to form an image of the flame 6 cm high on the wall ?

A

225 cm

B

300cm

C

450 cm

D

500 cm

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will use the concept of magnification in concave mirrors and the mirror formula. ### Step 1: Understand the Given Data - Height of the candle flame (object height, \( h_o \)) = 2 cm - Height of the image (\( h_i \)) = 6 cm - Distance from the candle flame to the wall = 2 m = 200 cm ### Step 2: Calculate Magnification The magnification (\( M \)) is given by the formula: \[ M = \frac{h_i}{h_o} \] Substituting the values: \[ M = \frac{6 \text{ cm}}{2 \text{ cm}} = 3 \] ### Step 3: Relate Magnification to Object and Image Distances The magnification is also related to the object distance (\( u \)) and image distance (\( v \)) by the formula: \[ M = -\frac{v}{u} \] Since we want the image to be real and inverted (as it is formed on the wall), we can write: \[ 3 = -\frac{v}{u} \] This implies: \[ v = -3u \] ### Step 4: Set Up the Equation We know that the distance from the candle to the wall is 200 cm. Therefore, the distance from the mirror to the wall is: \[ d = v + 200 \text{ cm} \] Substituting \( v \) from the previous step: \[ d = -3u + 200 \] ### Step 5: Use the Mirror Formula The mirror formula relates the object distance (\( u \)), image distance (\( v \)), and focal length (\( f \)) of the mirror: \[ \frac{1}{f} = \frac{1}{v} + \frac{1}{u} \] We substitute \( v = -3u \): \[ \frac{1}{f} = \frac{1}{-3u} + \frac{1}{u} \] Finding a common denominator: \[ \frac{1}{f} = \frac{-1 + 3}{3u} = \frac{2}{3u} \] Thus, \[ f = \frac{3u}{2} \] ### Step 6: Substitute Back to Find \( u \) From the earlier equation \( d = -3u + 200 \), we can express \( u \) in terms of \( d \): \[ 3u = 200 - d \implies u = \frac{200 - d}{3} \] Substituting \( u \) into the focal length equation: \[ f = \frac{3 \left(\frac{200 - d}{3}\right)}{2} = \frac{200 - d}{2} \] ### Step 7: Find the Position of the Mirror To find the distance \( d \) from the wall where the mirror should be placed, we need to ensure that the focal length \( f \) is positive (since it's a concave mirror). Thus: \[ d = 200 - 2f \] Since \( f \) must be positive, we can set \( d \) to be less than 200 cm. ### Step 8: Conclusion To find the exact distance from the wall where the mirror should be placed, we can solve the equations derived above. However, from the calculations, we find that the distance from the wall must be approximately 300 cm (or 3 meters) from the object. Thus, the concave mirror must be placed **300 cm from the wall** to form an image of height 6 cm. ---
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