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The orbital speed of an electron orbitin...

The orbital speed of an electron orbiting around the nucleus in a circular orbit of radius r is v. Then the magnetic dipole moment of the electron will be

A

ever

B

`(evr)/(2)`

C

`(ev)/(2r)`

D

`(vr)/(2e)`

Text Solution

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The correct Answer is:
To find the magnetic dipole moment of an electron orbiting around the nucleus in a circular orbit of radius \( r \) with orbital speed \( v \), we can follow these steps: ### Step 1: Understand the concept of magnetic dipole moment The magnetic dipole moment (\( \mu \)) of a current-carrying loop is given by the formula: \[ \mu = I \cdot A \] where \( I \) is the current and \( A \) is the area of the loop. ### Step 2: Determine the current due to the electron's motion The current \( I \) can be defined as the charge passing through a point per unit time. For an electron moving in a circular orbit: \[ I = \frac{Q}{T} \] where \( Q \) is the charge of the electron (denoted as \( e \)) and \( T \) is the time period for one complete revolution. ### Step 3: Calculate the time period \( T \) The time period \( T \) can be calculated using the formula for the circumference of the circular path divided by the speed: \[ T = \frac{2\pi r}{v} \] ### Step 4: Substitute \( T \) into the current formula Substituting \( T \) into the current formula gives: \[ I = \frac{e}{T} = \frac{e}{\frac{2\pi r}{v}} = \frac{e \cdot v}{2\pi r} \] ### Step 5: Calculate the area \( A \) of the circular orbit The area \( A \) of the circular orbit is given by: \[ A = \pi r^2 \] ### Step 6: Substitute \( I \) and \( A \) into the magnetic dipole moment formula Now, substituting \( I \) and \( A \) into the magnetic dipole moment formula: \[ \mu = I \cdot A = \left(\frac{e \cdot v}{2\pi r}\right) \cdot \left(\pi r^2\right) \] ### Step 7: Simplify the expression Simplifying the expression: \[ \mu = \frac{e \cdot v}{2\pi r} \cdot \pi r^2 = \frac{e \cdot v \cdot r}{2} \] ### Conclusion Thus, the magnetic dipole moment of the electron is: \[ \mu = \frac{e \cdot v \cdot r}{2} \] ### Final Answer The magnetic dipole moment of the electron is \( \frac{e \cdot v \cdot r}{2} \). ---
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