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A short bar magnet is placed in the magn...

A short bar magnet is placed in the magnetic meridian with its north pole pointing towards geographical south. A neutral point is found at a distance of 30 cm from the centre of the magnet. If the horizontal component of earth's field is 0.4G , calculate the magnetic moment of the magnet .

A

`7.44"ampere"xx "metre"`

B

`77.4"ab-ampere" xx cm`

C

`18.5"ampere" xx "metre"`

D

`185"ab-ampere" xx cm`

Text Solution

Verified by Experts

The correct Answer is:
B
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A 10 cm long bar magnet of magnetic moment 1.34 Am2 is placed in the magnetic meridian with its south pole pointing geographical south. The neutral point is obtained at a distance of 15 cm from the centre of the magnet. Calculate the horizontal component of earth’s magnetic field.

A bar magnet 30cm long is placed in magnetic meridian with its north pole pointing south. The neutral point is observed at a distance of 30cm from its centre. Calculate the pole strength of the magnet. Given horizontal component of earth's field is 0*34G .

Knowledge Check

  • A short bar magnet of magnetic moment 1.2Am^(2) is placed in the magnetic meridian with its south pole pointing the north. If a neutral point is found at a distance of 20cm from the centre of the magnet, the value of the horizontal component of the earth's magnetic field is

    A
    `3xx10^(-5)T`
    B
    `3xx10^(-4)T`
    C
    `3xx10^(3)T`
    D
    `3xx10^(-2)T`
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