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The difference between angular speed of ...

The difference between angular speed of minute hand and second hand of a clock is

A

`(59pi)/900rad//s`

B

`(59pi)/1800rad//s`

C

`(59pi)/2400rad//s`

D

`(59pi)/3600rad//s`

Text Solution

AI Generated Solution

The correct Answer is:
To find the difference between the angular speeds of the minute hand and the second hand of a clock, we can follow these steps: ### Step-by-Step Solution 1. **Understand Angular Speed**: Angular speed (ω) is defined as the angle covered per unit time. For a complete revolution, the angle covered is \(2\pi\) radians. 2. **Determine the Time Period of Each Hand**: - **Minute Hand (Tm)**: The minute hand takes 60 minutes to complete one full revolution. \[ T_m = 60 \text{ minutes} = 60 \times 60 \text{ seconds} = 3600 \text{ seconds} \] - **Second Hand (Ts)**: The second hand takes 60 seconds to complete one full revolution. \[ T_s = 60 \text{ seconds} \] 3. **Calculate Angular Speeds**: - **Angular Speed of Minute Hand (ωm)**: \[ \omega_m = \frac{2\pi}{T_m} = \frac{2\pi}{3600} \text{ rad/s} \] - **Angular Speed of Second Hand (ωs)**: \[ \omega_s = \frac{2\pi}{T_s} = \frac{2\pi}{60} \text{ rad/s} \] 4. **Find the Difference in Angular Speeds**: The difference between the angular speeds of the second hand and the minute hand is given by: \[ \Delta \omega = \omega_s - \omega_m \] Substituting the values we calculated: \[ \Delta \omega = \frac{2\pi}{60} - \frac{2\pi}{3600} \] 5. **Simplify the Expression**: To simplify, we can find a common denominator: \[ \Delta \omega = \frac{2\pi \cdot 60}{3600} - \frac{2\pi}{3600} = \frac{2\pi(60 - 1)}{3600} = \frac{2\pi \cdot 59}{3600} \] 6. **Final Result**: Thus, the difference in angular speeds of the minute hand and the second hand is: \[ \Delta \omega = \frac{59\pi}{1800} \text{ rad/s} \] ### Conclusion: The difference between the angular speed of the minute hand and the second hand of a clock is \(\frac{59\pi}{1800}\) rad/s. ---
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