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A mass of 5 kg is tied to a string of le...

A mass of 5 kg is tied to a string of length 1.0 m and is rotated in vertical circle with a uniform speed of `4m//s` . The tension in the string will be 130 N when the mass is at (g= 10`m//s^2`)

A

highest point

B

mid way

C

bottom

D

cannot be justified

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AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the forces acting on the mass when it is rotated in a vertical circle. We will use the concepts of centripetal force and gravitational force to find the angle θ at which the tension in the string is 130 N. ### Step-by-Step Solution: 1. **Identify the Given Values:** - Mass (m) = 5 kg - Length of the string (radius, r) = 1.0 m - Speed (v) = 4 m/s - Tension (T) = 130 N - Acceleration due to gravity (g) = 10 m/s² 2. **Draw the Free Body Diagram:** - When the mass is at an angle θ with the vertical, the forces acting on it are: - The tension (T) acting along the string towards the center of the circle. - The gravitational force (mg) acting downward. 3. **Set Up the Equation for Centripetal Force:** - The net centripetal force required to keep the mass moving in a circle is provided by the tension in the string minus the component of the gravitational force acting along the string. - The centripetal force (Fc) is given by: \[ F_c = \frac{mv^2}{r} \] - The gravitational force acting downward is: \[ F_g = mg \] - The component of the gravitational force acting along the string (when at angle θ) is: \[ F_{g,\text{along}} = mg \cos \theta \] 4. **Write the Equation:** - The equation for centripetal force can be written as: \[ T - mg \cos \theta = \frac{mv^2}{r} \] - Plugging in the values: \[ 130 - (5 \cdot 10) \cos \theta = \frac{5 \cdot (4^2)}{1} \] - Simplifying: \[ 130 - 50 \cos \theta = 80 \] 5. **Solve for cos θ:** - Rearranging the equation: \[ 130 - 80 = 50 \cos \theta \] \[ 50 = 50 \cos \theta \] \[ \cos \theta = 1 \] 6. **Find θ:** - Since \(\cos \theta = 1\), this implies: \[ \theta = 0^\circ \] - This means the mass is at the bottom-most point of the vertical circle. ### Final Answer: The angle θ at which the tension in the string is 130 N is \(0^\circ\). ---
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