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A particle moves along a circle of radius'r' with constant tangential acceleration. If the velocity of the particle is 'v' at the end of second revolution , after the revolution has started then the tangential accleration is

A

`(v^2)/(8pir)`

B

`(v^2)/(6pir)`

C

`(v^2)/(4pir)`

D

`(v^2)/(2pir)`

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The correct Answer is:
A
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