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A particle is moving in a circular path ...

A particle is moving in a circular path of radius a under the action of an attractive potential `U=-(k)/(2r^(2))`. Its total energy is :

A

zero

B

`-3/2k/a^2`

C

`-k/(4a^2)`

D

`k/(2a^2)`

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The correct Answer is:
A
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