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The orbital velocity of a body at height...

The orbital velocity of a body at height h above the surface of Earth is 36% of that near the surface of the Earth of radius R. If the escape velocity at the surface of Earth is 11.2 km `s_(-1)`, then its value at the height h will be

A

`11.2 kms^(-1)`

B

`sqrt(h/R)xx11.2kms^(-1)`

C

`9/(25)xx11.2kms^(-1)`

D

`sqrt(R/(h)xx11.2kma^(-1)`

Text Solution

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The correct Answer is:
C
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