Home
Class 12
PHYSICS
Two simple harmonic motions are given by...

Two simple harmonic motions are given by `y_(1) = a sin [((pi)/(2))t + phi]` and `y_(2) = b sin [((2pi)/( 3))t + phi]`. The phase difference between these after `1 s` is

A

`pi`

B

`pi/2`

C

`pi/4`

D

`pi/6`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • OSCILLATIONS

    TARGET PUBLICATION|Exercise Critical thinking|81 Videos
  • OSCILLATIONS

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING|135 Videos
  • MODEL QUESTION PAPER

    TARGET PUBLICATION|Exercise MODEL QUESTION PAPER -II|47 Videos
  • QUESTION PAPER 2019

    TARGET PUBLICATION|Exercise MCQ|45 Videos

Similar Questions

Explore conceptually related problems

Two S.H.Ms are given by y_(1) = a sin ((pi)/(2) t + (pi)/(2)) and y_(2) = b sin ((2pi)/(3) t + (pi)/(2)) . The phase difference between these after 1 second is

Two waves are given by y_(1) = a sin (omega t - kx) and y_(2) = a cos (omega t - kx) . The phase difference between the two waves is

Two simple harmonic motion are represented by equations y_(1) = 4 sin (10 t + phi) rArr y_(2) = 5 cos 10t What is the phase difference between their velocities ?

Two simple harmonic motions are represented by y_(1)= 10 "sin" omega t " and " y_(2) =15 "cos" omega t . The phase difference between them is

Statement-I : Two simple harmonic motions are given by y_(1) = 10sin (3pi t+(pi)/(4)) and y_(2) = 5(sin 3pit +sqrt(3) cos 3pi t) . These have amplitudes in the ratio 1:1 . Statement-II : y_(1) & y_(2) respresents two waves of amplitudes 5 & 5sqrt(3) . So the resultant amplitude is 10 .

Two simple harmonic motions are represented by y_(1)=5 [sin 2 pi t + sqrt(3)cos 2 pi t] and y_(2) = 5 sin (2pit+(pi)/(4)) The ratio of their amplitudes is

The simple harmonic vibrations of two particles are y_(1)= 5sin (100t) and y_(2) = 4 cos (100t + pi/4) . The phase difference between both particles is

Two partical A and B execute simple harmonic motion according to the equation y_(1) = 3 sin omega t and y_(2) = 4 sin [omega t + (pi//2)] + 3 sin omega t . Find the phase difference between them.

Two simple harmonic motions A and B are given respectively by the following equations. y_(1)=asin[omegat+(pi)/(6)] y_(2)=asin[omegat+(3pi)/(6)] Phase difference between the waves is

Two simple harmonic motions are represented by the equations y_(1) = 10 sin (3pit + (pi)/(4)) and y_(2) = 5 (3 sin 3 pi t+sqrt(3) cos 3 pi t) . Their amplitudes are in the ratio of