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A body of mass 36 g moves with S.H.M. of...

A body of mass 36 g moves with S.H.M. of amplitude A = 13 cm and time period T = 12 s. At time t = 0, the displacement x is + 13 cm. The shortest time of passage from x = + 6.5 cm to x = - 6.5 cm is

A

4s

B

2s

C

6s

D

3s

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The correct Answer is:
To solve the problem, we need to determine the shortest time taken for a body in Simple Harmonic Motion (S.H.M.) to move from a displacement of +6.5 cm to -6.5 cm. Given the parameters of the motion, we can follow these steps: ### Step 1: Understand the parameters of S.H.M. - Mass of the body, \( m = 36 \, \text{g} = 0.036 \, \text{kg} \) - Amplitude, \( A = 13 \, \text{cm} = 0.13 \, \text{m} \) - Time period, \( T = 12 \, \text{s} \) - Initial displacement at \( t = 0 \), \( x(0) = +13 \, \text{cm} \) ### Step 2: Write the equation of motion for S.H.M. Since the body starts from the positive extreme, we can express the displacement \( x(t) \) as: \[ x(t) = A \cos(\omega t) \] where \( \omega \) is the angular frequency given by: \[ \omega = \frac{2\pi}{T} = \frac{2\pi}{12} = \frac{\pi}{6} \, \text{rad/s} \] ### Step 3: Find the time when \( x = +6.5 \, \text{cm} \) Set \( x(t) = 6.5 \, \text{cm} = 0.065 \, \text{m} \): \[ 0.065 = 0.13 \cos\left(\frac{\pi}{6} t\right) \] \[ \cos\left(\frac{\pi}{6} t\right) = \frac{0.065}{0.13} = \frac{1}{2} \] The angle whose cosine is \( \frac{1}{2} \) is \( \frac{\pi}{3} \) radians. Thus: \[ \frac{\pi}{6} t_1 = \frac{\pi}{3} \implies t_1 = 2 \, \text{s} \] ### Step 4: Find the time when \( x = -6.5 \, \text{cm} \) Set \( x(t) = -6.5 \, \text{cm} = -0.065 \, \text{m} \): \[ -0.065 = 0.13 \cos\left(\frac{\pi}{6} t\right) \] \[ \cos\left(\frac{\pi}{6} t\right) = -\frac{1}{2} \] The angle whose cosine is \( -\frac{1}{2} \) is \( \frac{2\pi}{3} \) radians. Thus: \[ \frac{\pi}{6} t_2 = \frac{2\pi}{3} \implies t_2 = 4 \, \text{s} \] ### Step 5: Calculate the time difference The time taken to move from \( +6.5 \, \text{cm} \) to \( -6.5 \, \text{cm} \) is: \[ \Delta t = t_2 - t_1 = 4 \, \text{s} - 2 \, \text{s} = 2 \, \text{s} \] ### Final Answer The shortest time of passage from \( x = +6.5 \, \text{cm} \) to \( x = -6.5 \, \text{cm} \) is **2 seconds**.
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