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The total energy of a simple harmonic os...

The total energy of a simple harmonic oscillator is `3xx10^(-5)` J and maximum force acting on the body is `1.5xx10^(-3)` N. If the period of the motion is 2s and initial phase is `30^(@)`, then the equation of motion will be

A

`x=0.4" "sin(pit+pi/6)`

B

`x=0.4" "sin(2pit+pi/6)`

C

`x=0.4" "sin(pit+pi/6)`

D

`x=0.4" "sin(2pit+pi/6)`

Text Solution

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The correct Answer is:
C
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