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A simple · pendulum of length L is hangi...

A simple · pendulum of length L is hanging from a rigid support on the ceiling of a stationary train. If the train moves forward with an acceleration a, then the time period of the pendulwn will be

A

`2pisqrt(L/((g^2+a^2)^(1//2))`

B

`2pisqrt(L/((g^2-a^2)^(1//2))`

C

`2pisqrt(L/((g+a)))`

D

`2pisqrt(L/((g-a)))`

Text Solution

Verified by Experts

The correct Answer is:
A
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