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A simple pendulum performs simple harmon...

A simple pendulum performs simple harmonic motion about `x=0` with an amplitude a ans time period T. The speed of the pendulum at `x = (a)/(2)` will be

A

`(piAsqrt3)/T`

B

`(piA)/T`

C

`(piAsqrt3)/(2T)`

D

`(3pi^2A)/T`

Text Solution

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The correct Answer is:
A
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