Home
Class 12
PHYSICS
Assertion : if work done in increasing ...

Assertion : if work done in increasing th size of a soap film from 10 cm `xx` 4 cm to `10cm xx8cm `is `2xx10^(-4)`J, then the surface tension is `5xx10^(-4)N m^(-1)`
Reason : work done = surface tension `xx` increase in area .

A

Assertion is true ,Reason is true , ,Reason is a correct explanation for Assertion

B

Assertion is True , reason Is True reason is not a correct explanation for asserion

C

Assertion is True , Reason is False

D

Assertion is false but reason is true

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • SURFACE TENSION

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING|72 Videos
  • SURFACE TENSION

    TARGET PUBLICATION|Exercise EVALUATION TEST|21 Videos
  • SURFACE TENSION

    TARGET PUBLICATION|Exercise EVALUATION TEST|21 Videos
  • STATIONARY WAVES

    TARGET PUBLICATION|Exercise EVALUATION TEST|16 Videos
  • WAVE MOTION

    TARGET PUBLICATION|Exercise MCQ 7.1|61 Videos

Similar Questions

Explore conceptually related problems

If work done in increasing the size of a soap film from 10 cm x 6 cm to 10 cm x 11 cm is 2xx10^(-4) J , then the surface tension is

If work done in increasing the size of a soap film from 10cmxx6cmxx to 10cmxx11xm is 2xx10^-4H , then the surface tension is

The workdone in increasing the size of a soap film from 10 cm xx 6 cm to 10 cm xx 11 cm is 3 xx 10^(-4)J. The surface tension of the film is

The work done in increasing the size of a soap film from 10cmxx6cm to 10cmxx11cm is 3xx10^-4 Joule. The surface tension of the film is

The work done in increasing the size of a soap film from 10 cm × 6 cm to 10 cm × 11 cm is 3 xx10^(-4) joule . The surface tension of the film is

The work done in increasing the size film with dimensions 8cm xx3.75xm to 10cmxx6cm is 2xx10^(-4)J . The surface tension of the film in (N)/(m) is

The work done in increasing the size of a rectangular soap film with dimensions 8 cm x 3.75 cm to 10 cm x 6 cm is 2 xx 10^(-4) J . The surface tension of the film in (N m^(-1)) is

The work done in increasing the radius of a soap bubble from 4 cm to 5 cm is Joule (given surface tension of soap water to be 25xx10^(-3)N//m)

Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. (surface tension of soap solution = 0.3 Nm^(-1))

The work done in increasing the size of a rectangular soap film with dimensions 8cm times3.75cm to 10cm times6cm is 2times10^(-4)J .The surface tension of the film in N/m is

TARGET PUBLICATION-SURFACE TENSION -CRITICAL THINKING
  1. A clean glass plate of length 9.8 cm , breadth 4 cm an thicness 0.2...

    Text Solution

    |

  2. Two drops of soap equal radius r coalesce to form a single drop under...

    Text Solution

    |

  3. Assertion : if work done in increasing th size of a soap film from 1...

    Text Solution

    |

  4. The surface tension of soap is T . The work done in blowing a soap bu...

    Text Solution

    |

  5. The work done in blowing a soap bubble of radius r of the solution of ...

    Text Solution

    |

  6. If work W is done in blowing a bubble of radius R from a soap solution...

    Text Solution

    |

  7. Energy needed in breaking a drop of radius R into n drops of radii r i...

    Text Solution

    |

  8. The work done in increasing the size of a soap film from 10 cm × 6 cm ...

    Text Solution

    |

  9. The surface tension of a liquid is 5Nm^-1. If a thin film formed on a ...

    Text Solution

    |

  10. A soap bubble is blown with the help of mechanical pump at the mouth o...

    Text Solution

    |

  11. The work done in blowing a soap bubble from a radius of 6 cm to 9 cm i...

    Text Solution

    |

  12. The surface tension of a soap solution is 2.1xx10^(-2) N//m . The work...

    Text Solution

    |

  13. Two soap bubbles, each of radius r, coaleses in vacuum under isotermal...

    Text Solution

    |

  14. If W is amount of work done in forming a soap bubble of volume V , the...

    Text Solution

    |

  15. Surface area of a soap bubble is 1.3xx10^(-4) m^2. The work done to ...

    Text Solution

    |

  16. Two mercury drops each of radius r merge to form a bigger drop. Calcul...

    Text Solution

    |

  17. A water film is formed between two stratght parallel wires of length ...

    Text Solution

    |

  18. A film of water is formed between two straight parallel wires of le...

    Text Solution

    |

  19. A film of soap solution is formed in a rectnagular wire frame of leng...

    Text Solution

    |

  20. If n drops of a liquid , each with surface energy E , join to form a s...

    Text Solution

    |