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Energy needed in breaking a drop of radi...

Energy needed in breaking a drop of radius `R` into `n` drops of radii `r` is given by

A

`4piT(nr^2-R^2)`

B

`4/3pi(r^3 n-R^2)`

C

`8piT(R^2-nr^2)`

D

`4piT(nr^2+R^2)`

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The correct Answer is:
A
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