Home
Class 12
PHYSICS
Surface area of a soap bubble is 1.3xx1...

Surface area of a soap bubble is `1.3xx10^(-4) m^2`. The work done to doble the surface area will be ( Surface tension for soap solution = `3xx10^(-3)`N//m )

A

`5.85 xx10^(-7)` joule

B

`7.8xx10^(-7)` joule

C

`1.95xx10^(-7)` joule

D

`3.9xx10^(-7)` joule

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Topper's Solved these Questions

  • SURFACE TENSION

    TARGET PUBLICATION|Exercise COMPETITIVE THINKING|72 Videos

  • SURFACE TENSION

    TARGET PUBLICATION|Exercise EVALUATION TEST|21 Videos

  • SURFACE TENSION

    TARGET PUBLICATION|Exercise EVALUATION TEST|21 Videos

  • STATIONARY WAVES

    TARGET PUBLICATION|Exercise EVALUATION TEST|16 Videos

  • WAVE MOTION

    TARGET PUBLICATION|Exercise MCQ 7.1|61 Videos

Similar Questions

Explore conceptually related problems

The work done in blowing a soap bubble of 10 cm radius is (Surface tension of the soap solution is 3/100 N/m)

Find the radius of the soap bubble if 44times10^(-6)J of work is done in flowing the soap bubble surface tension of soap solution 7times10^(-2)N/m

The work done in blowing a soap bubble of radius 0.2 m is (the surface tension of soap solution being 0.06 N/m )

The work done in blowing a soap bubble from a radius of 6 cm to 9 cm if surface tension of soap solution is 25xx10^(-3) N//m , is

What will be the work done in blowing a soap bubble of radius 1 cm to 2 cm ? (If surface tension of soap solution is 25 xx 10^(-3) N/m)

What will be the work done in blowing out a soap bubble of radius 0.4 cm? The surface tension of soap solution is 30 xx 10^(-3)" N/m".

The work done in forming a soap film of size 10 cm xx 10 cm will be , it if the surface tension of soap solution is 3xx 10^(-2) N/m

The amount of work done in forming a soap bubble of radius r = 1 cm (surface tension T = 3 xx 10^(-2) N//m ) is

TARGET PUBLICATION-SURFACE TENSION -CRITICAL THINKING
  1. Two soap bubbles, each of radius r, coaleses in vacuum under isotermal...

    Text Solution

    |

  2. If W is amount of work done in forming a soap bubble of volume V , the...

    Text Solution

    |

  3. Surface area of a soap bubble is 1.3xx10^(-4) m^2. The work done to ...

    Text Solution

    |

  4. Two mercury drops each of radius r merge to form a bigger drop. Calcul...

    Text Solution

    |

  5. A water film is formed between two stratght parallel wires of length ...

    Text Solution

    |

  6. A film of water is formed between two straight parallel wires of le...

    Text Solution

    |

  7. A film of soap solution is formed in a rectnagular wire frame of leng...

    Text Solution

    |

  8. If n drops of a liquid , each with surface energy E , join to form a s...

    Text Solution

    |

  9. The surface energy of a liquid drop is u . If it is split into 1000 e...

    Text Solution

    |

  10. The work done in splitting a drop of water of 1 mm radius into 64 ide...

    Text Solution

    |

  11. A spherical liquid drop of radius R is divided into eight equal drople...

    Text Solution

    |

  12. A drop of liquid of diameter 2.8 mm breaks up into 125 identical drop...

    Text Solution

    |

  13. The excess pressure in a soap bubble of diameter 8 cm and surface te...

    Text Solution

    |

  14. If the value of excess pressure in a soap bubble is four times that of...

    Text Solution

    |

  15. Two soap bubble have volumes in the ratio 8:1. The ratio of excess pr...

    Text Solution

    |

  16. A capillary tube of radius r is dipped in a liquid of density rho and...

    Text Solution

    |

  17. The most approprite graph between height (h) of the liquid column in a...

    Text Solution

    |

  18. The radius of the bore of a capillary tube is r and the angle of conta...

    Text Solution

    |

  19. The meniscus of mercury in a capillary tube is 1.356 cm below plane ...

    Text Solution

    |

  20. A capillary tube is held vertically in water . The internal radius of ...

    Text Solution

    |