Energy needed in breaking a drop of radius `R` into `n` drops of radii `r` is given by

Options

A. `4piR^2Tn^(2//3)`
B. `4piR^2T(n^(2//3)-1)`
C. `4piR^2T(n^(1//3)-1)`
D. `4piR^2T(n-n^(2//3))`

Answer

C