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When two sound waves with a phase differ...

When two sound waves with a phase difference of ` pi //2`, and each having amplitude A and frequency `omega` , are superimposed on each other, then the maximum amplitude and frequency of resultant wave is

A

` ( A) /(sqrt( 2)):( omega )/(2) `

B

` (A)/(sqrt(2)) : omega `

C

` sqrt A :(omega)/( 2) `

D

` sqrt A : omega `

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The correct Answer is:
A
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TARGET PUBLICATION-WAVE MOTION -MCQ 7.1
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