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Both strings shown in figure, are made of same material and have same cross section. The pulleys are light. The wave speed of a transverse wave in the string AB is `v_1` and in CD it is` v_2`. Then `v_1/v_2` is

A

`1`

B

2

C

`sqrt2`

D

`(1)/(sqrt( 2))`

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The correct Answer is:
A
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TARGET PUBLICATION-WAVE MOTION -MCQ 7.1
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