An open pipe is resonance is its `2^(nd)` harmonic with tuning fork of freqency `f_(1)`. Now it is closed at one end. If the frequency of the tuning fork is increases slowly from `f_(1)`, then agaain a resonance is obtained with `a_(1)` frequency `f_(2)`. if in this case the pipe vibrates `n^(th)` harmonics, then

Options

A. `n=3, f_(2)=(3)/(4)f_(1)`
B. `n=3, f_(2)=(5)/(4)f_(1)`
C. `n=5, f_(2)=(5)/(4)f_(1)`
D. `n=5, f_(2)=(3)/(4)f_(1)`

Answer

C