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In a pipe opened at both ends n(1) and n...

In a pipe opened at both ends `n_(1)` and `n_(2)` be the frequencies corresponding to vibrating lengths `L_(1)` and `L_(2)` respectively .The end correction is

A

`(n_(1)l_(2)-n_(2)l_(2))/(2(n_(1)-n_(2)))`

B

`(n_(2)l_(2)-n_(1)l_(1))/(2(n_(2)-n_(1)))`

C

`(n_(2)l_(2)-n_(1)l_(1))/(2(n_(1)-n_(2)))`

D

`(n_(1)l_(1)-n_(2)l_(2))/((n_(1)-n_(2)))`

Text Solution

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The correct Answer is:
C
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