In Melde's experiment in parallel position the mass of the pan is `M_(0)`. When a mass `m_(1)` is kept in the pan, the number of loops formed is `p_(1)`. For the mass `m_(2)`, the number of loops, formed is `p_(2)`. Then the mass of the pan `M_(0)`, in terms of `m_(1) , m_(2), p_(1) " and " p_(2)` is given by

Options

A. `m_(0)=(p_(1)^(2)-p_(2)^(2))/(m_(2)p_(2)^(2)-m_(1)p_(1)^(2))`
B. `m_(0)=(m_(2)p_(2)^(2)-m_(1)p_(1)^(2))/(p_(1)^(2)-p_(2)^(2))`
C. `m_(0)=(m_(2)p_(2)^(2)+m_(1)p_(1)^(2))/(p_(1)^(2)-p_(2)^(2))`
D. `m_(0)=(m_(2)p_(2)^(2)-m_(1)p_(1)^(2))/(p_(1)^(2)+p_(2)^(2))`

Answer

B