At N.T.P., sample of equal volumes of chlorine and oxygen are taken. Now ratio of number of molecules is

Options

A. `1:1`
B. `32:27`
C. `2:1`
D. `16:14`

Answer

To find the ratio of the number of molecules of chlorine (Cl₂) and oxygen (O₂) at Normal Temperature and Pressure (NTP), we can follow these steps:

### Step-by-Step Solution:

1. **Understanding NTP Conditions**:
At Normal Temperature and Pressure (NTP), the conditions are defined as a temperature of 0°C (273.15 K) and a pressure of 1 atm. Under these conditions, equal volumes of any ideal gas contain an equal number of molecules.

2. **Using Avogadro's Law**:
Avogadro's Law states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules. Therefore, if we take equal volumes of chlorine and oxygen at NTP, the number of molecules in each gas will be the same.

3. **Setting Up the Ratio**:
Let’s denote:
- \( N_{O_2} \) = number of molecules of oxygen
- \( N_{Cl_2} \) = number of molecules of chlorine

Since the volumes are equal and the conditions are the same, we can write:
\[ N_{O_2} = N_{Cl_2} \]

4. **Calculating the Ratio**:
The ratio of the number of molecules of chlorine to the number of molecules of oxygen is:
\[ \frac{N_{Cl_2}}{N_{O_2}} = 1 \]

5. **Conclusion**:
Therefore, the ratio of the number of molecules of chlorine to the number of molecules of oxygen at NTP is 1:1.

### Final Answer:
The ratio of the number of molecules of chlorine to the number of molecules of oxygen at NTP is **1:1**.

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