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Velocities of three molecules are 2,3 and 4 m/s. Ratio of mean velocity to R.M.S velocity is

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lt1

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1

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gt1

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gt2

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To solve the problem of finding the ratio of mean velocity to root mean square (RMS) velocity for three molecules with velocities of 2 m/s, 3 m/s, and 4 m/s, we can follow these steps: ### Step 1: Calculate the Mean Velocity (V_mean) The mean velocity is calculated using the formula: \[ V_{\text{mean}} = \frac{V_1 + V_2 + V_3}{n} \] where \( V_1, V_2, V_3 \) are the velocities of the molecules and \( n \) is the number of molecules. Substituting the values: \[ V_{\text{mean}} = \frac{2 + 3 + 4}{3} = \frac{9}{3} = 3 \, \text{m/s} \] ### Step 2: Calculate the RMS Velocity (V_rms) The RMS velocity is calculated using the formula: \[ V_{\text{rms}} = \sqrt{\frac{V_1^2 + V_2^2 + V_3^2}{n}} \] First, we need to calculate the squares of the velocities: \[ V_1^2 = 2^2 = 4, \quad V_2^2 = 3^2 = 9, \quad V_3^2 = 4^2 = 16 \] Now, sum these squares: \[ V_1^2 + V_2^2 + V_3^2 = 4 + 9 + 16 = 29 \] Now, substitute this into the RMS formula: \[ V_{\text{rms}} = \sqrt{\frac{29}{3}} \] ### Step 3: Calculate the Ratio of Mean Velocity to RMS Velocity Now, we can find the ratio of mean velocity to RMS velocity: \[ \text{Ratio} = \frac{V_{\text{mean}}}{V_{\text{rms}}} = \frac{3}{\sqrt{\frac{29}{3}}} \] To simplify this, we can multiply the numerator and denominator by \(\sqrt{3}\): \[ \text{Ratio} = \frac{3\sqrt{3}}{\sqrt{29}} \] ### Step 4: Final Result The ratio of mean velocity to RMS velocity is: \[ \text{Ratio} = \frac{3\sqrt{3}}{\sqrt{29}} \]
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TARGET PUBLICATION-KINETIC THEORY OF GASES AND RADIATION -critical thinking
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