Rate of cooling of a body is 0 .2° C/min...

Rate of cooling of a body is 0 .2° C/min, when excess temperature is 20° C. The proportionality constant is

0.01

0.02

0.03

0.04

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A hot body is kept in cooler surroundings. Its rate of cooling is 3^(@)C /min when its temperature is 60^(@)C and 1.5^(@)C / min when its temperature is 45^(@)C . Determine the temperature of the surroundings and the rate of cooling when the temperature of the body is 40^(@)C

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Newton’s law of cooling says that the rate of cooling of a body is proportional to the temperature difference between the body and its surrounding when the difference in temperature is small. (a) Will it be reasonable to assume that the rate of heating of a body is proportional to temperature difference between the surrounding and the body (for small difference in temperature) when the body is placed in a surrounding having higher temperature than the body? (b) Assuming that our assumption made in (a) is correct estimate the time required for a cup of cold coffee to gain temperature from 10^(@)C to 15^(@)C when it is kept in a room having temperature 25^(@)C . It was observed that the temperature of the cup increases from 5^(@)C to 10^(@)C in 4 min

A cup of coffee cools from 90^0 C to 80^0 C in t minutes when the room temperature is 20^0 C . The time taken by a similar cup of coffee to cool from 80^0 C to 60^0 C at a room temperature same at 20^0 C is

A body cools at the rate of 3^(@)C// min when its temperature is 50^(@)C . If the temperature of surroundings is 25^(@)C then the rate of cooling of the body at 40^(@)C is

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