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A Carnot refrigerator absorbs heat from ...

A Carnot refrigerator absorbs heat from water at O °C and gives it to a room at 27 °C. When it converts 2 kg of water at 0°C into ice. at 0°C, the work.done is (Latent heat of fusion of ice= 333 x `10^3Jkg^(-1)`)

A

`25xx10^3` J

B

`82xx10^3` J

C

`65.87xx10^3` J

D

`92.52xx10^3` J

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The correct Answer is:
C
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A Carnot refrigerator extracts heat from water at 0^@C and rejects it to room at 24.4^@C . The work required by the refrigerator for every 1 kg of water converted into ice is (Latent heat of ice= 336 kJ kg^(-1) )

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Calculate the amount of heat energy to be supplied to convert 2 kg of ice at 0^@C completely into water at 0^@C if latent heat of fusion for ice is 80 cal/g.

Find the heat required to convert 20 g of iceat 0^(@)C into water at the same temperature. ( Specific latent heat of fusion of ice =80 cal//g )

Calculate the amount of heat energy to be supplied to convert 4 kg of ice at 0^@C completely into water at 0^@C if latent heat of fusion for ice is 80 cal/g.

Refrigerator is an apparatus which takes heat from a cold body, work is done on it and the work done together with the heat absorbed is rejected to the source. An ideal refrigerator can be regarded as Carnot's ideal heat engine working in the reverse direction. The coefficient of performance of refrigerator is defined as beta = ("Heat extracted from cold reservoir")/("work done on working substance") = (Q_(2))/(W) = (Q_(2))/(Q_(1)- Q_(2)) = (T_(2))/(T_(1) - T_(2)) A Carnot's refrigerator takes heat from water at 0^(@)C and discards it to a room temperature at 27^(@)C . 1 Kg of water at 0^(@)C is to be changed into ice at 0^(@)C. (L_(ice) = 80"kcal//kg") What is the work done by the refrigerator in this process ( 1 "cal" = 4.2 "joule" )

Refrigerator is an apparatus which takes heat from a cold body, work is done on it and the work done together with the heat absorbed is rejected to the source. An ideal refrigerator can be regarded as Carnot's ideal heat engine working in the reverse direction. The coefficient of performance of refrigerator is defined as beta = ("Heat extracted from cold reservoir")/("work done on working substance") = (Q_(2))/(W) = (Q_(2))/(Q_(1)- Q_(2)) = (T_(2))/(T_(1) - T_(2)) A Carnot's refrigerator takes heat from water at 0^(@)C and discards it to a room temperature at 27^(@)C . 1 Kg of water at 0^(@)C is to be changed into ice at 0^(@)C. (L_(ice) = 80"kcal//kg") How many calories of heat are discarded to the room?

Calculate the amount of heat required to convert5g of ice of 0^(@)C into water at 0^(@)C . ( Specific latent heat of fusion of ice 80 cal //g )

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