Home
Class 12
PHYSICS
In potentiometer experiment, a cell is b...

In potentiometer experiment, a cell is balanced by length 120 cm. When a cell is shunted by resistance of `5Omega`, the balancing length is 80 cm. The internal resistance of cell is

A

`2.5Omega`

B

`3Omega`

C

`4Omega`

D

`5Omega`

Text Solution

Verified by Experts

Promotional Banner

Topper's Solved these Questions

  • CURRENT ELECTRICITY

    TARGET PUBLICATION|Exercise Critical Thinking|24 Videos

  • CURRENT ELECTRICITY

    TARGET PUBLICATION|Exercise Competitive Thinking|48 Videos

  • CIRCULAR MOTION

    TARGET PUBLICATION|Exercise EVALUATION TEST|11 Videos

  • ELASTICITY

    TARGET PUBLICATION|Exercise Evaluation test|14 Videos

Similar Questions

Explore conceptually related problems

In potentiometer experiment, a cell is balanced by length 120cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In a potentiometer experiment the balancing with a cell is at length 240 cm. On shunting the cell with a resistance of 2Omega , the balancing length becomes 120 cm.The internal resistance of the cell is

In an experiment to determine the internal resistance of a cell with potentiometer, the balancing length is 165 cm. When a resistance of 5 ohm is joined in parallel with the cell the balancing length is 150 cm. The internal resistance of cell is

In a potentiometer the balancing with a cell is at length of 220cm. On shunting the cell with a resistance of 3Omega balance length becomes 130cm. What is the internal resistance of this cell.

A cell of e.m.f. 1.2 V is balanced by 150 cm of potentiometer wire. When the cell is shunted by a resistance of 4 Omega , the balancing length is reduced by 30 cm. What is the internal resistance of the cell ?

The emf of cell is balanced by balancing length 450 cm . When the resistance of 10 Omega is connected across the cell, balancing length changes by 100 cm. The internal resistance of a cell is

In potentiometer experiment, a cell of emf 1.25 V gives balancing length of 30 cm. If the cell is replaced by another cell, then balancing length is found to be 40 cm. What is the emf of second cell ?

In an experiment to find the internal resistance of a cell by a potentiometer, a balance was obtained for 50 cm length of the potentiometer wire, with a cell of e.m.f. 2V. When the cell was shunted by a resistance of 2 Omega , the balancing length of the potentiometer wire was 40 cm. What was the internal resistance of the cell ?

In a potentiometer experiment, the galvanometer shows no deflection when a cell is connected across 60 cm of the potentiometer wire. If the cell is shunted by a resistance of 6 Omega , the balance is obtained across 50 cm of the wire. The internal resistance of the cell is