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A galvanometer of resistance 99 Omega re...

A galvanometer of resistance 99 `Omega` requires 5 mA current for full scale deflection. It can be converted into an ammeter of range 0.5 A by connecting a shunt resistance of

A

`3 Omega`

B

`1 Omega`

C

`2 Omega`

D

`4 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B
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A galvanometer of resistance 120Omega gives full scale deflection for a current of 5mA. How can it be converted into an ammeter of range 0 to 5A? Also determine the net resistance of the ammeter.

The resistance of a pivoted type galvanometer is 8Omega and current for full scale deflection on it is 0*01A . This galvanometer is to be converted into an ammeter of 5A range. The only shunt available is 0*02Omega . Find the value of R to be connected in series with the galvanometer coil, figure.

Knowledge Check

  • A galvanometer has a resistance of 118Omega and gives full scale deflection for a current of 50 m A. if it is required to convert into an ammeter of range 3A, the shunt resistance should be

    A
    `0.2 Omega`
    B
    `0.28Omega`
    C
    `2Omega`
    D
    `2.8Omega`

  • A galvanometer of resistance 50Omega gives full scale deflection when a current 10^(-3)A is passed through it converted into an ammeter to measure 0.5A current.

    A
    `50//499 Omega` in parallel
    B
    `9//20 Omega` in parallel
    C
    `2//99 Omega` in parallel
    D
    `20//99 Omega` in parallel

  • A galvanometer of internal resistance 100 Omega has a full scale deflection current of 1mA . To convert it into a voltmeter of range 0-10V , the resistance to be connected is

    A
    `9000 Omega` in Series
    B
    `10,000 Omega` in Series
    C
    `9,900 Omega` in Series
    D
    `9,800 Omega` in Series

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