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A current I flows in a conducting wire o...

A current I flows in a conducting wire of lenth L. If we bent it in a circular form, then calculate its magnetic dipole moment.

A

`(IL)/(4pi)`

B

`(4pi)/(IL^(2))`

C

`4 pi IL^(2)`

D

`(IL^(2))/(4pi)`

Text Solution

Verified by Experts

The correct Answer is:
D
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Knowledge Check

  • A current I is flowing in a conductor of length L when it is bent in the form of a circular loop its magnetic moment

    A
    `(IL)/(4pi)`
    B
    `(4pi)/(IL^(2))`
    C
    `4piIL^(2)`
    D
    `(IL^(2))/(4pi)`

  • A steady current flow in a long wire. It is bent into a circular loop of one turn and the magnetic field at the centre of the coil is B. If the same wire is bent into a circular loop of n turns, the magnetic field at the centre of the coil is

    A
    `(B)/(n)`
    B
    nB
    C
    `nB^(2)`
    D
    `n^(2)B`

  • A magnetised steel wire of length L has a magnetic moment of 3.14 Am^(2) . If the wire is bent into a semicircular arc, then what would be its new magnetic moment? (assume that the poles are situated at the ends of the wire.)

    A
    `5 Am^(2)`
    B
    `4 Am^(2)`
    C
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