Hydrogen `(._(1)H^(1))`, Deuterum `(._(1)H^(2))`, singly ionised Hellium `(._(2)He^(4))^(+)` and doubly ionised lithium `(._(3)Li^(6))^(++)` all have one electron around the nucleus. Consider an electron tranition from `n=2` to `n=1`. If the wave lengths of emitted radiation are `lambda_(1),lambda_(2),lambda_(3)` and `lambda_(4)` respectively then approximately which one of the follwing is correct ?

Options

A. `4lambda_(1) = 2lambda_(2)= 2lambda_(3) = lambda_(4)`
B. `lambda_(1) = 2lambda_(2) =2 lambda_(3) = lambda_(4)`
C. `lambda_(1)= lambda_(2) = 4lambda_(3) = 9 lambda_(4)`
D. `lambda_(1) =2lambda_(2) =3 lambda_(3) = 4lambda_(4)`

Answer

C