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The decay constant of radio isotope is l...

The decay constant of radio isotope is `lambda`. If `A_(1) and A_(2)` are its activities at times `t_(1) and t_(2)` respectively, the number of nuclei which have decayed during the time `(t_(1)-t_(2))`

A

`A_(1)t_(1) - A_(2)t_(2)`

B

`A_(1)- A_(2)`

C

`(A_(1) -A_(2))//lambda`

D

`lambda(A_(1)-A_(2))`

Text Solution

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The correct Answer is:
C
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