A charged particle is associated from rest through a certain potential difference. The de-Broglie wavelength is `lambda_(1)` when it is accelerated through `V_(1)` and is `lambda_(2)` when accelerated through `V_(2)`. The ratio `lambda_(1)//lambda_(2)` is

Options

A. `V_(1)^(3//2) :V_(2)^(3//2)`
B. `V_(2)^(1//2): V_(1)^(1//2)`
C. `V_(1)^(1//2) : V_(2)^(1//2)`
D. `V_(1)^(2): V_(2)^(2)`

Answer

B