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The energy of an electron having de-Brog...

The energy of an electron having de-Brogilie wavelength `lamda` is
(hwere, h=Plank's constant, m = mass of electron)

A

`h/(2m lambda)`

B

`h^(2)/(2mlambdap^(2))`

C

`h^(2)/(2m^(2)lambda^(2))`

D

`h^(2)/(2m^(2)lambda)`

Text Solution

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The correct Answer is:
B
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